1. A
point charge of +2.0 x 10-6 C is 3.0 cm distance from a second point
of charge – 5.0 x 10-6 C. calculate the magnitude of the force on
each charge
Solution
Given : q1 = +2.0 x 10-6
C
q2 = -5.0 x 10-6C
r = 3.0 cm
= 3.0 x 10-2 m
Find : F = …?
Answer :
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2. Two
point charge; q1 = +6.0µC and q2 = - 2.0 µC are separated
by a distance of 4.0 cm in a vacuum, find the electric force acting on each
charge!
Solution
Given: q1
= +6.0 x 10-6 C
q2 = -2.0 x 10-6C
r = 4.0 cm = 4.0 x 10-2
m
Find : F = …?
Answer :
3. Two
equal charges of magnitude 4.0 µC experience an electrostatic force 160 N. how
far apart are the centers of two charges?
Solution
Given : q1 = q2
= 4x 10-6C
F = 160 N
Find : r = …?
Answer :
