1.
Sonar is emitted
from the ship to measure the depth of the sea. It is received by the receiver in
0.8 seconds. If the speed of sound in water is 1500 m/s, calculate the depth of
the sea.
Solution
Data
: t = 0.8 s
V = 1500 m/s
Question
: d = ….?
Answer
:
d
= ( vt ) /2 = ( 1500 m/s x 0.8 s ) : 2 = 600 m
2.
Sonar is emitted
from the ship to measure the depth of the sea. It is received by the receiver in
1.2 seconds. If the speed of sound in water is 1480 m/s, calculate the depth of
the sea.
Solution
Data
: t = 1.2 s
V = 1480 m/s
Question
: d = ….?
Answer
:
d
= ( vt ) /2 = ( 1480 m/s x 1.2 s ) : 2 = 888 m
3.
Sonar is emitted
from ship. The depth of the sea is 660m. Calculate the time transmitted until
it received a back receiver. (The speed of sound in water is 1400 m/s)
Solution
Data
: d = 660 m
V = 1400 m/s
Question
: t = ….?
Answer
:
t
= 2d/v = 2x 660 m : 1400 m/s = 0.94 s
4.
Sonar is emitted
from ship. The depth of the sea is 1.5 km. Calculate the time transmitted until
it is received back by the receiver. (The speed of sound in water is 1500 m/s)
Solution
Data
: d = 1.5 km = 1500 m
V = 1500 m/s
Question
: t = ….?
Answer
:
t
= 2d/v = 2 x 1500 m : 1500 m/s = 2 s
5.
Sonar is emitted
from the ship. The depth of the sea is 315 m. If the total time after emitting and
received back by the receiver is 0.42 s, calculate the speed of sound in water.
Solution
Data
: d = 315 m
t =
0.42 s
Question
: v= ….?
Answer
:
V
= 2d / t = 2x 315 m : 0.42 s = 1500 m/s
6.
Sonar is emitted
from the ship. The depth of the sea is 1.8 km. If the total time after emitting
until it is received back by the receiver is 18/7 seconds. Calculate the speed of
sound in the seawater.
Solution
Data
: d = 1.8 km = 1800 m
t = 18/7 s
Question
: v = ….?
Answer
:
v
= 2d/t = 2x 1800 m : 18/7 s = 1400 m/s
7.
Pedro shouts loudly. The sound is reflected back by the wall. He can hear his echo in 0.22 s. Calculate the
distance between Pedro and the wall. The speed of sound in air is 340 m/s.
Solution
Data
: v= 340 m/s
t = 0.22 s
Question
: d = ….?
Answer
:
d=
vt / 2 = 340 m/s x 0.22 s : 2 = 37.4 m
8.
Pauline shouts
loudly. The sound is reflected back by the wall.
He can hear his echo in 0.40 s. Calculate the distance between Pauline and the wall. The speed of sound in air is 330
m/s.
Solution
Data
: v= 330 m/s
t = 0.40 s
Question
: d = ….?
Answer
:
d=
vt / 2 = 330 m/s x 0.40 s : 2 = 66 m
