COULOMB’S LAW PRACTICE PROBLEM

 

1.     A point charge of +2.0 x 10^-6 C is 3.0 cm distance from a second point of charge – 5.0 x 10^-6 C. calculate the magnitude of the force on each charge

Solution

Given       : q₁ = +2.0 x 10^-6 C

                  q₂ = -5.0 x 10^-6C

                    r = 3.0 cm = 3.0 x 10^-2 m

Find  : F = …?

Answer   :

2.     Two point charge; q₁ = +6.0µC and q₂ = - 2.0 µC are separated by a distance of 4.0 cm in a vacuum, find the electric force acting on each charge!

Solution

Given: q₁ = +6.0 x 10^-6 C

            q₂ = -2.0 x 10^-6C

              r = 4.0 cm = 4.0 x 10^-2 m

Find : F = …?

Answer   :

 

3.     Two equal charges of magnitude 4.0 µC experience an electrostatic force 160 N. how far apart are the centers of two charges?

Solution

Given  : q₁ = q₂ = 4x 10^-6C

              F = 160 N

Find : r = …?

Answer :